Well, it curves upward, so it's not linear. Just a slight curve though.
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curve.PNG [2.22KiB |Viewed 10427 times ]
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| Summer was long, need a refresher http://www.ferrousmoon.com:80/forums/viewtopic.php?f=55&t=1456 |
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| Author: | eddieringle [Wed Sep 03, 2008 4:26 pm ] |
| Post subject: | Summer was long, need a refresher |
Okay, I let 25% of what I learned in Algebra last year slip away over the Summer like all the experts say, and now coming into Geometry the teacher gave us a simple assignment. I just need to be retaught the methods to doing this assignment. Quite simply, I need to write three functions each containing the data points from three graphs I made. Yeah, my brain isn't exactly a secure fortress, stuff slips out a lot and goes on cruises in the Caribbean and junk like that, never coming back. Also, I have no idea why I added that random and useless statement just now. |
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| Author: | FinalWarrior [Wed Sep 03, 2008 5:50 pm ] |
| Post subject: | Re: Summer was long, need a refresher |
Uh, what are the graphs, exactly? Lines, parabolas, hyperbolas, ellipses, circles? Every graph has its own function ( = equation). -- Griffinhart |
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| Author: | eddieringle [Wed Sep 03, 2008 5:54 pm ] |
| Post subject: | Re: Summer was long, need a refresher |
Well, it curves upward, so it's not linear. Just a slight curve though. Attachment: curve.PNG [2.22KiB |Viewed 10427 times ] |
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| Author: | FinalWarrior [Sat Sep 06, 2008 10:31 am ] |
| Post subject: | Re: Summer was long, need a refresher |
Looks like a semiparabola. y = a(x-h)^2 + k, x > SomeValue, where a stretches or squishes the graph, h moves the graph left or right, and k moves the graph up or down. -- Griffinhart |
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| Author: | eddieringle [Sat Sep 06, 2008 5:32 pm ] |
| Post subject: | Re: Summer was long, need a refresher |
Thanks for that, went to class and all the other kids thought it was half a parabola too. |
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| Author: | FinalWarrior [Sat Sep 06, 2008 8:17 pm ] |
| Post subject: | Re: Summer was long, need a refresher |
You're just lucky that I'm reviewing functions (and logarithms/exponentials)in my AP Calc class right now... or I'd be about as stuck as you were. Speaking of which, I should probably study for the test... meh, oh well. -- Griffinhart PS. By the way, can anyone show me how to solve for x in the following equation? e^x + e^(-x) = 3 I know logarithms are involved, and I know what the answer is (it's something like x = (5 * sqrt(3)) / 2), I just don't know how to actually solve the equation. I mean, if you took the log of both sides of the equation, you'd end up with x + -x = ln 3 And that makes no sense. |
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| Author: | mc2m [Sun Sep 07, 2008 5:13 am ] |
| Post subject: | Re: Summer was long, need a refresher |
First: ln (e^x + e^(-x)) != x + -x To solve this you have to solve a quadratic expression e^x + e^(-x) = 3 <=> e^(x²) + 1 = 3e^x <=> e^(x²) - 3e^x + 1 = 0 e^x = y <=> y² - 3y + 1 = 0 Now you can find the answer. |
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| Author: | FinalWarrior [Sun Sep 07, 2008 5:30 am ] |
| Post subject: | Re: Summer was long, need a refresher |
Quote: First: ln (e^x + e^(-x)) != x + -x
Oh, I see... I thought you had to take the log of each individual part, not the entire side of the equation, because of the addition.Okay, how did you go from Quote: e^x + e^(-x) = 3
toQuote: e^(x²) + 1 = 3e^x
? That's the only part I don't understand.-- Griffinhart |
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| Author: | mc2m [Sun Sep 07, 2008 6:01 am ] |
| Post subject: | Re: Summer was long, need a refresher |
I made a mistake... It's not e^(x²) + 1 = 3e^x but e^(2x) + 1 = 3e^x e^x + e^(-x) = 3 <=> e^x + 1/e^x = 3 <=> e^x ( e^x + 1/e^x) = 3e^x <=> e^(2x) + 1 = 3e^x ... |
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| Author: | FinalWarrior [Sun Sep 07, 2008 6:17 am ] |
| Post subject: | Re: Summer was long, need a refresher |
Ah, okay. That makes more sense. Thank you so very much for the help!  -- Griffinhart |
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