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     Post subject:Math challenge
    PostPosted:Wed Sep 19, 2007 12:20 pm 
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    Joined:Sun Feb 12, 2006 8:56 pm
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    Okay guys, here is a challenge I have from 8th grade accelerated Alegebra. It's about functions. The whole class was puzzled with it. We need to find the rule of the function.

    x | y
    in | out
    0 | 0 (pattern: + 1 = next y)
    1 | 1 (+ 2 = next y)
    2 | 3 (+ 3 = next y)
    3 | 6 (+ 4 = next y)
    4 | 10 (+ 5 = next y)

    EDIT: A pattern in this function is that the next y will always equal the previous y + num++ (as in, the value of the number you are adding to y will increase by 1 each time, of course it starts at 1. I added it to the table above). So obviously you can figure out the value of y, but we need the rule of the function, and you can't say prev y + num++, not in real life at least :P).

    I used a picture of bowling pins in my head, (triangles) each time you added another row and the number of pins you added also increased by 1 each time.

    Now, seeing as this isn't programming, and my programming mind is thinking to put y in an array so I could access them like y[0], y[1], etc. I am having a hard time figuring it out. It is our only homework, and two of my friends that have the same class in another hour came up to me and said:

    "We asked Mr. Maus if he thought Eddie Ringle could do it, and he said: '"Maybe, because he's kind of quiet."'."

    :P

    So if you need anymore information let me know.

    Thank you.

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    PostPosted:Wed Sep 19, 2007 12:45 pm 
    Literally Nine
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    It's just a triangular number.

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    PostPosted:Wed Sep 19, 2007 1:49 pm 
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    Miah... We're THIRTEEN YEAR OLDs. :P

    We may be in Accelerated Alegbra but we aren't that advanced. :P

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    PostPosted:Wed Sep 19, 2007 2:24 pm 
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    Joined:Sat Mar 11, 2006 8:28 am
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    lol, triangle umbers, learned that in grade 5 hehe.

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    PostPosted:Wed Sep 19, 2007 2:27 pm 
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    Joined:Sun Oct 30, 2005 3:40 pm
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    Quote:
    Miah... We're THIRTEEN YEAR OLDs. :P

    We may be in Accelerated Alegbra but we aren't that advanced. :P
    It's not that hard, it just looks complex, just look at the = signs. you probably want
    Code:
    ( x ( x + 1 ) ) / 2

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    PostPosted:Wed Sep 19, 2007 2:43 pm 
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    Joined:Sun Feb 12, 2006 8:56 pm
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    ChaosR and me figured it out over MSN... Thank you everyone for your input and thank you Miah for your, interesting equation...

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    PostPosted:Wed Sep 19, 2007 4:06 pm 
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    Joined:Sat Jun 03, 2006 3:51 am
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    Funny, you guys thought "triangular numbers", I'm sitting here thinking "acceleration!"

    Frickin' AP Physics...

    -- Griffinhart

    PS. Not to sound condescending/insulting, but I'm sorry; you're in 8th grade accelerated Algebra (Is that like Accelerated Reading? Man, I miss elementary school...) and you couldn't confuzzle this one out on your own?

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    PostPosted:Wed Sep 19, 2007 7:52 pm 
    Literally Nine
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    Joined:Tue Mar 01, 2005 9:00 am
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    Quote:
    ChaosR and me figured it out over MSN... Thank you everyone for your input and thank you Miah for your, interesting equation...
    Bah.

    You'll need to read between the ='s if you ever seek help from me. That image was pulled from wiki, but I tend to give full disclosure like this anyway.

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    PostPosted:Thu Sep 20, 2007 2:39 pm 
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    @Tycho: Maybe an idea for a C++ challenge, calculating Pascal's Triangle?

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    PostPosted:Fri Sep 21, 2007 5:39 am 
    Literally Nine
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    Quote:
    @Tycho: Maybe an idea for a C++ challenge, calculating Pascal's Triangle?
    I'll investigate.

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